A Beam free at the Ends and loaded in the Middle.—A Beam uniformly loaded.—A Beam loaded in the Middle, whose Ends are secured.—A Beam supported at one end and loaded at the other. A BEAM FREE AT THE ENDS AND LOADED |
Formula, P=6080 | areaofsection×depth |
span |
Number of Experiment. | Dimensions. | Mean of the observations of the breaking load in lbs. | P. Calculated breaking load in lbs. | Difference of the observed and calculated values. | ||
---|---|---|---|---|---|---|
Span. | Breadth. | Depth. | ||||
1 | 40"·0 | 1"·0 | 1"·0 | 152 | 152 | 0·0 |
2 | 40"·0 | 0"·5 | 1"·0 | 77 | 76 | -1·0 |
3 | 40"·0 | 1"·0 | 0"·5 | 38 | 38 | 0·0 |
4 | 40"·0 | 0"·5 | 0"·5 | 19 | 19 | 0·0 |
5 | 30"·0 | 1"·0 | 0"·5 | 59 | 51 | -8·0 |
6 | 30"·0 | 0"·5 | 0"·5 | 25 | 25 | 0·0 |
7 | 20"·0 | 1"·0 | 0"·5 | 74 | 76 | +2·0 |
8 | 20"·0 | 0"·5 | 0"·5 | 36 | 38 | +2·0 |
9 | 10"·0 | 1"·0 | 0"·5 | 154 | 152 | -2·0 |
10 | 10"·0 | 0"·5 | 0"·5 | 68 | 76 | +8·0 |
381. In the first column is a series of figures for convenience of reference. The next three columns are occupied with the dimensions of the beams. By span is meant the distance between the points of support; the real length is of course greater; the depth is that dimension of the beam which is vertical. The fifth column gives the mean of two observations of the breaking load. Thus for example, in experiment No. 5 the two beams used were each 36"×1"×0"·5, they were placed on points of support 30" distant, so the span recorded is 30": one of the
382. We shall endeavour to elicit from these observations the laws which connect the breaking load with the span, breadth, and depth of the beam.
383. Let us first examine the effect of the span; for this purpose we bring together the observations upon beams of the same section, but of different spans. Sections of 0"·5×0"·5 will be convenient for this purpose; Nos. 4, 6, 8, and 10 are experiments upon beams of this section. Let us first compare 4 and 8. Here we have two beams of the same section, and the span of one (40") is double that of the other (20"). When we examine the breaking weights we find that they are 19 lbs. and 36 lbs.; the former of these numbers is rather more than half of the latter. In fact, had the breaking load of 40" been ¾ lb. less, 18·25 lbs., and had that of 20" been ½ lb. more, 36·5 lbs., one of the breaking loads would have been exactly half the other.
384. We must not look for perfect numerical accuracy in these experiments; we must only expect to meet with approximation, because the laws for which we are in search are in reality only approximate laws. Wood itself is variable in quality, even when cut from the same piece: parts near the circumference are different in strength from those nearer the centre; in a young tree they are generally weaker, and in an old tree generally stronger. Minute differences in the grain, greater or less perfectness in the seasoning, these are also among the circumstances which prevent one piece of timber from being identical
385. But you will find, I think, that, making reasonable allowances for such difficulties as do occur, the laws on the whole represent the experiments very closely.
386. We shall, then, assume that the breaking weight of a bar of 40" is half that of a bar of 20" of the same section, and we ask, Is this generally true? is it true that the breaking weight is inversely proportional to the span? In order to test this hypothesis, we can calculate the breaking weight of a bar of 30" (No. 6), and then compare the result with the observed value; if the supposition be true, the breaking weight should be given by the proportion—
30":40"::19:Answer.
The answer is 25·3 lbs.; on reference to the table we find 25 lbs. to be the observed value, hence our hypothesis is verified for this bar.
387. Let us test the law also for the 10" bar, No. 10—
10":40"::19:Answer.
The answer in this case is 76, whereas the observed value is 68, or 8 lbs. less; this does not agree very well with the theory, but still the difference, though 8 lbs., is only about 11 or 12 per cent. of the whole, and we shall still retain the law, for certainly there is no other that can express the result as well.
389. We next inquire as to the effect of the breadth of the beam upon its strength? For this purpose we compare experiments Nos. 3 and 4: we there find that a bar 40"×1"×0"·5 is broken by a load of 38 lbs., while a bar just half the breadth is broken by 19 lbs. We might have anticipated this result, for it is evident that the bar of No. 3 must have the same strength as two bars similar to that of No. 4 placed side by side.
390. This view is confirmed by a comparison of Nos. 7 and 8, where we find that a 20" bar takes twice the load to break it that is required for a bar of half its breadth. The law is not quite so well verified by Nos. 5 and 6, for half the breaking weight of No. 5, namely 29·5 lbs., is more than 25, the observed breaking weight of No. 6: a similar remark may be made about Nos. 9 and 10.
391. Supposing we had a beam of 40" span, 2" broad, and 0"·5 deep, we can easily see that it is equivalent to two bars like that of No. 3 placed side by side; and we infer generally that the strength of a bar is proportional to its breadth; or to speak-more definitely, if two beams have the same span and depth, the ratio of their breaking loads is the same as the ratio of their breadths.
392. We next examine the effect of the depth of a beam upon its strength. In experimenting upon a beam placed edgewise, a precaution must be observed, which would not be necessary if the same beam were to be broken flatwise. When the load is suspended, the beam, if merely laid edgewise on the supports, would almost certainly turn over; it is
394. The strength of a beam 40"×0"·5×1" is four times as great as the strength of 40"×0"·5×0"·5, though the quantity of wood is only twice as great in one as in the other. In general we may state that if a beam were bisected by a longitudinal cut, the strength of the beam would be halved when the cut was horizontal, and unaltered when the cut was vertical; thus, for example, two beams of experiment No. 4, placed one on the top of the other, would break with about 40 lbs., whereas if the same rods were in one piece, the breaking load would be nearly 80 lbs.
395. This may be illustrated in a different manner. I have here two beams of 40"×1"×0"·5 superposed; they form one beam, equivalent to that of No. 1 in bulk, but I find that they break with 80 lbs., thus showing that the two are only twice as strong as one.
396. I take two similar bars, and, instead of laying them loosely one
397. We shall be able by a little consideration to understand the reason why a bar is stronger edgewise than flatwise. Suppose I try to break a bar across my knee by pulling the ends held one in each hand, what is it that resists the breaking? It is chiefly the tenacity of the fibres on the convex surface of the bar. If the bar be edgewise, these fibres are further away from my knee and therefore resist with a greater moment than when the bar is flatwise: nor is the case different when the bar is supported at each end, and the load placed in the centre; for then the reactions of the supports correspond to the forces with which I pulled the ends of the bar.
398. We can now calculate the strength of any rectangular beam of pine:
Let us suppose it to be 12' long, 5" broad, and 7" deep. This is five times as strong as a beam 1" broad and 7" deep for we may conceive the original beam to consist of 5 of these beams placed side by side (Art 391); the beam 1" broad and 7" deep, is 7 times as strong as a beam 7" broad, 1" deep (Art. 393). Hence the original beam must be 35 times as
144":40"::152:Answer.
The answer is 42·2 lbs., and thus the breaking load of the original beam is about 10,300 lbs.
399. It will be useful to deduce the general expression for the breaking load of a beam l" span, b" broad, and d" deep, supported freely at the ends and laden in the centre.
Let us suppose a bar l" long, and 1"×1" in section. The breaking load is found by the proportion—
l:40::152:Answer;
and the result obtained is 6080/l. A beam which is d" broad, l" span, and 1" deep, would be just as strong as d of the beams l"×1"×1" placed side by side; of which the collective strength would be—
6080 | |
————— | ×d. |
l |
If such a beam, instead of resting flatwise, were placed edgewise, its strength would be increased in the ratio of its depth to its breadth—that is, it would be increased d-fold—and would therefore amount to
6080 | |
————— | ×d². |
l |
We thus learn the strength of a beam 1" broad, d" deep, and l" span. The strength of b of these beams placed side by side, would be
6080 | |
————— | ×d²×b. |
l |
Since b d is the area of the section, we can express this result conveniently by saying that the breaking load in lbs. of a rectangular pine beam is equal to
6080× | areaofsection×depth |
span |
the depth and span being expressed in inches linear measure, and the section in square inches.
400. In order to test this formula, we have calculated from it the breaking loads of all the ten beams given in Table XXIV. and the results are given in the sixth column. The difference between the amount calculated and the observed mean breaking weight is shown in the last column.
401. Thus, for example, in experiment No. 7 the span is 20", breadth, 1", depth 0"·5; the formula gives, since the area is 0"·5,
0·5×0·5 | ||
P=6080 | ————— | =76 |
20 |
This agrees sufficiently with 74 lbs., the mean of two observed values.
402. Except in experiments Nos. 5 and 10, the differences are very small, and even in these two cases the differences are not sufficient to make us doubt that we have discovered the correct expression for the load generally sufficient to produce fracture.
areaofsection×depth | |
1500× | —————————— |
span |
Probably a smaller coefficient than 1500 would often be used by the cautious builder, especially when the beam was liable to sudden blows or shocks. The coefficient obtained from small selected rods such as we have used would also be greater than that found from large beams in which imperfections are inevitable.
404. Had we adopted any other kind of wood we should have found a similar formula for the breaking weight, but with a different numerical coefficient. For example, had the beams been made of oak the number 6080 must be replaced by a larger figure.
A BEAM UNIFORMLY LOADED.
405. We have up to the present only considered the case where the load is suspended from the centre of the beam. But in the actual employment of beams the load is not generally applied in this manner. See in the rafters which support a roof how every inch in the entire length has its burden of slates to bear. The beams which support a warehouse floor have to carry their load in whatever manner the goods are disposed: sometimes, as for example in a grain-store, the pressure will be tolerably uniform along the beams, while if the weights be irregularly scattered on the floor, there will be corresponding inequalities in the mode in which the loads are distributed over the beams. It will therefore be useful for us to examine the strength of a beam when its load is applied otherwise than at the centre.
Fig. 53.
407. We proceed to break this beam. Adding weights to the tray, we see that it yields with 117 lbs., and cracks across between c and d. On reference to Table XXIV. we find from experiment No. 2 that a similar bar was broken by 77 lbs. at the centre; now ³/2×77=115·5; hence we may state with sufficient approximation that the bar is half as strong again when the load is suspended from the two points of trisection as it is when suspended from the centre. It is remarkable that in breaking the beam in this manner the fracture is equally likely to occur at any point between c and d.
Fig. 54.
In an experiment actually tried, a beam 40"×0"·5×1" placed edgewise was found to support ten 14 lb. weights ranged as in the figure; one or two stone more would, however, doubtless produce fracture.
409. We infer from these considerations that beams loaded in the manner in which they are usually employed are considerably stronger than would be indicated by the results in Table XXIV.
EFFECT OF SECURING THE ENDS OF A BEAM
UPON ITS STRENGTH.
410. It has been noticed during the experiments that when the weights are suspended from a beam and the beam begins to deflect, the ends curve upwards from the supports. This bending of the ends is for example shown in Fig. 54. If we restrain the ends of the beam from bending up in this manner, we shall add very considerably to its strength. This we can do by clamping them down to the supports.
412. When the beam gives way under these circumstances, there is not only a fracture in the centre, but each of the halves are also found to be broken across near the points of support; the necessity for three fractures instead of one explains the increase of strength obtained by restraining the ends to the horizontal direction.
413. In structures the beams are generally more or less secured at each end, and are therefore more capable of bearing resistance than would be indicated by Table XXIV. From the consideration of Arts. 408 and 411, we can infer that a beam secured at each end and uniformly loaded would require three or four times as much load to break it as would be sufficient if the ends were free and if the load were applied at the centre.
BEAMS SECURED AT ONE END AND
LOADED AT THE OTHER.
In the case we shall examine, a b is a pine beam of dimensions 20"×0"·5×0"·5, and we find that, when w reaches 10 lbs., the beam breaks. In experiment No. 8, Table XXIV., a similar beam
Fig. 55.
We shall presently have occasion to apply some of the results obtained by the experiments made in the lecture now terminated.