[p 38 ] PROBLEM XI. TO DRAW ANY CURVE IN A HORIZONTAL OR VERTICAL PLANE .

Previous

[Geometric diagram]
Fig.28.

Let AB, Fig.28., be the curve.

Inclose it in a rectangle, CDEF.

Fix the position of the point C or D, and draw the rectangle. (ProblemVIII. Coroll.I.)[Footnote 20]

Let CDEF, Fig.29., be the rectangle so drawn.

[Geometric diagram]
Fig.29.

If an extremity of the curve, as A, is in a side of the rectangle, divide the side CE, Fig.29., so that AC shall be (in perspective ratio) to AE as AC is to AE in Fig.28. (Prob.V. Cor.II.)

Similarly determine the points of contact of the curve and rectangle e, f, g.

If an extremity of the curve, as B, is not in a side of the rectangle, let [p39] fall the perpendiculars Ba, Bb on the rectangle sides. Determine the correspondent points a and b in Fig.29., as you have already determined A, B, e, and f.

From b, Fig.29., draw bB parallel to CD,[Footnote 21] and from a draw aB to the vanishing-point of DF, cutting each other in B. Then B is the extremity of the curve.

Determine any other important point in the curve, as P, in the same way, by letting fall Pq and Pr on the rectangle’s sides.

Any number of points in the curve may be thus determined, and the curve drawn through the series; in most cases, three or four will be enough. Practically, complicated curves may be better drawn in perspective by an experienced eye than by rule, as the fixing of the various points in haste involves too many chances of error; but it is well to draw a good many by rule first, in order to give the eye its experience.[Footnote 22]

COROLLARY.

If the curve required be a circle, Fig.30., the rectangle which incloses it will become a square, and the curve will have four points of contact, ABCD, in the middle of the sides of the square.

[Geometric diagram]
Fig.30.

Draw the square, and as a square may be drawn about a circle in any position, draw it with its nearest side, EG, parallel to the sight-line.

Let EF, Fig.31., be the square so drawn.

[p40]
Draw its diagonals EF, GH; and through the center of the square (determined by their intersection) draw AB to the vanishing-point of GF, and CD parallel to EG. Then the points ABCD are the four points of the circle’s contact.

[Geometric diagram]
Fig.31.

On EG describe a half square, EL; draw the semicircle KAL; and from its center, R, the diagonals RE, RG, cutting the circle in x, y.

From the points x y, where the circle cuts the diagonals, raise perpendiculars, Px, Qy, to EG.

From P and Q draw PP', QQ', to the vanishing-point of GF, cutting the diagonals in m, n, and o, p.

Then m, n, o, p are four other points in the circle.

Through these eight points the circle may be drawn by the hand accurately enough for general purposes; but any number of points required may, of course, be determined, as in ProblemXI.

The distance EP is approximately one-seventh of EG, and may be assumed to be so in quick practice, as the error involved is not greater than would be incurred in the hasty operation of drawing the circle and diagonals.

It may frequently happen that, in consequence of associated [p41] constructions, it may be inconvenient to draw EG parallel to the sight-line, the square being perhaps first constructed in some oblique direction. In such cases, QG and EP must be determined in perspective ratio by the dividing-point, the line EG being used as a measuring-line.

[Obs. In drawing Fig.31. the station-point has been taken much nearer the paper than is usually advisable, in order to show the character of the curve in a very distinct form.

If the student turns the book so that EG may be vertical, Fig.31. will represent the construction for drawing a circle in a vertical plane, the sight-line being then of course parallel to GL; and the semicircles ADB, ACB, on each side of the diameter AB, will represent ordinary semicircular arches seen in perspective. In that case, if the book be held so that the line EH is the top of the square, the upper semicircle will represent a semicircular arch, above the eye, drawn in perspective. But if the book be held so that the line GF is the top of the square, the upper semicircle will represent a semicircular arch, below the eye, drawn in perspective.

If the book be turned upside down, the figure will represent a circle drawn on the ceiling, or any other horizontal plane above the eye; and the construction is, of course, accurate in every case.]

[Footnote 20: Or if the curve is in a vertical plane, Coroll. to ProblemIX. As a rectangle may be drawn in any position round any given curve, its position with respect to the curve will in either case be regulated by convenience. See the Exercises on this Problem, in the Appendix, p.85.] Return to text

[Footnote 21: Or to its vanishing-point, if CD has one.] Return to text

[Footnote 22: Of course, by dividing the original rectangle into any number of equal rectangles, and dividing the perspective rectangle similarly, the curve may be approximately drawn without any trouble; but, when accuracy is required, the points should be fixed, as in the problem.] Return to text

                                                                                                                                                                                                                                                                                                           

Clyx.com


Top of Page
Top of Page