Let P, Fig.4., be the given point. [Geometric diagram] Let its direct distance be DT; its lateral distance to the left, DC; and vertical distance beneath the eye of the observer, CP. [Let GH be the Sight-line, S the Sight-point, and T the Station-point.] It is required to fix on the plane of the picture the position of the point P. [p11] Join CT, cutting GH in Q. From Q let fall the vertical line QP'. Join PT, cutting QP in P'. P' is the point required. If the point P is above the eye of the observer instead of below it, CP is to be measured upwards from C, and QP' drawn upwards from Q. The construction will be as in Fig.5. [Geometric diagram] And if the point P is to the right instead of the left of the [p12] observer, DC is to be measured to the right instead of the left. The figures 4. and 5., looked at in a mirror, will show the construction of each, on that supposition. Now read very carefully the examples and notes to this problem in AppendixI. (page 69). I have put them in the Appendix in order to keep the sequence of following problems more clearly traceable here in the text; but you must read the first Appendix before going on. |